call by Reference is possible?

Hi ,

I suggest u dont jump directly on the questions....

If u r planning for the certification then pls go thru the ebooks and study material first.

for ur info .....

"A" is inside a

"B" inside b

now whent it invokes method

"x" is pointing to "a" block means hving "A"and

"Y" is pointing to "b" block means hving "B"and

after x.append(y).

inside block x and a value becomes "AB"

after y=x; means now y is pointing to "x" block

now come back to ur main method

when it prints a n b u will get AB n B

java_usera at 2007-7-15 3:59:29 >

Java is ALWAYS pass by value.

When you are passing objects, it passes the object reference by value.

You can change the contents of that object, and the changes will be reflected in the calling method.In your example, the stringBuffer.append call is an example of that.

However if you assign a completely new value to that parameter, THAT change won't be reflected in the calling class

So assigning y = x changes it in your method, but has no effect on the calling method.

Does that help?

evnafets

evnafetsa at 2007-7-15 3:59:29 >

Because in x=y, you are updating the x variable to point to another value. This change is (naturally) limited to the scope of x.

In x.append(y), you are not updating the x variable, but the object x refers to. So this change will be visible for all references to that object, even when x has passed from scope.

Message was edited by:

johannef

johannefa at 2007-7-15 3:59:29 >