Time range
I have a log file which contains entries like
8-25-2006 11:43:08, orange
8-25-2006 13:50:14, apple
8-25-2006 13:55:14, orange
I want to classify what time this log entry is made, so what I want is to have an array of 24 that would contain the number of messages logged within that range such that
arr[0] = 0; // 0:00:01 - 1:00:00
arr[1] = 0; // 1:00:01 - 2:00:00
:
:
:
arr[10] = 1; // 11:00:01 - 12:00:00
arr[11] = 0; // 12:00:01 - 13:00:00
arr[12] = 2; // 13:00:01 - 14:00:00
:
:
:
arr[23] = 0; // 23:00:01 - 0:00:00
Can anyone suggest what is the best way to go around this? Thank you in advance!
[707 byte] By [
mpanga] at [2007-10-3 3:32:55]
correction pls
arr[0] = 0; // 0:00:01 - 1:00:00
arr[1] = 0; // 1:00:01 - 2:00:00
:
:
:
arr[10] = 1; // 10:00:01-11:00:00 instead of 11:00:01 - 12:00:00
and so on
Logic
Get hour,minute and second value of time field from log file into
int hour,min,sec resp;
//so hour =0 for any value between 0:00:01 - 1:00:00
// hour =1 for any value between 1:00:01 - 2:00:00
arr[hour]++;
// will increment respective counter
Critical problem
Hour value bet 0:00:00 to 0:59:59 hour will be 0
but for 1:00:00 hour=1
hence for 1:00:00 counter arr[1] will be incremented
to avoid this have a check condition
if min ==0 and sec ==0 // hour =1 for 1:00:00
hour--; // 1:00:00 should be included to arr[0]
fair code
hour=....;
sec=..;
min=..;
if (sec==0&& min==0)
hour--;
arr[hour]++;
arr[hour]++;
> Logic
> Get hour,minute and second value of time field from
> log file into
> int hour,min,sec resp;
Logic: get the hour from the log file and ignore minutes and seconds completely. Hour will be 1..24 or 0..23, adjust as required.
You will have an error of 1 second every hour which I am sure you can cope with.
ejpa at 2007-7-14 21:27:13 >
