Calling thread.start() more than once concurrently
Hi, I got a simple doubt that may feel awkward or absurd to people who are well versed in the java threading concepts. I just thought of it and as I couldn't get an easy answer I am posting this.
Consider a class that implements the runnable interface. The run() method of the class is implemented with just a System.out.println(). If I make an instance of this class, say 't' in the main method and calling t.start() susequently twice or thrice; an illegal ThreadStateException will be thrown. The code snippet is as follows:
ThreadTest t = new ThreadTest();
t.start();
t.start();
...........
...........
It is understood that state of the thread object is changed to run state and so, if it is again started, it must be thrown. So if I put a Thread.sleep() inbetween these two subsequent calls assuming that the main method thread will be sleeping. So there is sufficient time for the first thread to terminate and then only the second will start - still the same exception is being thrown. I tried putting the synchronized qualifier for run too, still no effect - the same only happening. Why the java thread object is made in such a way that once the thread changes it state from Runnable to Running and then finally to dead state, it can be restated back to Runnable state, such that the start() method can be called again. Is it possible or not? Please post your comments.
