i wrote a servlet but i dont know where to put my class file.
i tried to put it under web-inf/class anywhere under the insallation folder but its not working (he cant find the page).
can anyone tell me where exactly i need to put the class file?
im working with apache tomcat 5.5
thanks
You need to create a directory under 'webapps' that will be the name of your application. Place the class files in WEB-INF/classes under that folder. If I named the folder 'foo' and my Servlet was 'BarServlet', the URL to test would be:
http://localhost:8080/foo/BarServlet
If you place the files in the 'root' (the directory is actually named 'root'), then you do not need to specify the name of your web application in the URL.
- Saish
its still not working.
here is what i did till now-
i downloaded & install apache tomcat 5.5
i created a simple servlet-
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class FirstServlet extends HttpServlet{
public void doGet(HttpServletRequest requset,HttpServletResponse response)
throws ServletException,IOException
{PrintWriter out=response.getWriter();
out.println("done!");
}
}
build it and the class file i put under -instalationDir/webapps/NameOfProject/WEB-INF/classes
and in the browser im writing-
http://localhost:8080/NameOfProject/FirstServlet
and he cant find the page
what am i missing?
thanks in advanced.
You should have a web.xml file for each web app that you declare. any settings you declare in this web.xml file are applicable to that web application only.
in the web.xml file, you should have a <web-app> tag. Under this you will map your servlet like:
<servlet>
<servlet-name>DataServlet</servlet-name>
<servlet-class>DataServlet</servlet-class>
</servlet>
declare all servlet classes likle this, and then start with URL mapping like this:
<servlet-mapping>
<servlet-name>DataServlet</servlet-name>
<url-pattern>/Data</url-pattern>
</servlet-mapping>
So, for each servlet you need to indiocate its .class file and specify the URl mapping.
in the above example, assuming we have a webapp "foo" under webapps folder,
the web.xml file should be in the folder:
<Tomcat installation dir>\webapps\Mtool\WEB-INF
and the url to access it is:
http://localhost:8080/foo/Data
Hope this helps
thats my web.xml-
?xml version="1.0" encoding="ISO-8859-1"?>
<web-app>
<servlet>
<servlet-name>FirstServlet</servlet-name>
<servlet-class>ServletTry</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>FirstServlet</servlet-name>
<url-pattern>/FirstServlet</url-pattern>
</servlet-mapping>
i put it under directory webapps/ServletTry
i guess its wrong...
</web-app>
Okay. Look at your url-pattern, that is what must go after the web app name. So, if you have a folder structure that looks like this:
Tomcat Root
webapps
ServletTry
WEB-INF
classes
FirstServlet.class
And your url-mapping is 'FirstServlet', then the URL you submit is:
http://localhost:8080/ServletTry/FirstServlet
- Saish
<<servlet-class>ServletTry</servlet-class> >
actually he has indicated "ServletTry" as his class in the web.xml file.
ppl1, you should indicate the name of the .class file for your servlet in the tags for <servlet-class>
and the name by which you want your servlet to be referred to in:
<url-pattern> tag.
Under the webapps folder, you define your individual web applications as separate folders. You should create a folder with the name you want your web application to be known as under webapps folder.
its looking like that-
tomcat 5.5
webapps
- ServletTry
-- WEB-INF
--classes
-FirstServlet.class
my web.xml is-
<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app>
<servlet>
<servlet-name>FirstServlet</servlet-name>
<servlet-class>FirstServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>FirstServlet</servlet-name>
<url-pattern>/FirstServlet</url-pattern>
</servlet-mapping>
</web-app>
i put it under directory ServletTry.
in the browser i wrote-
http://localhost:8080/ServeltTry/FirstServlet
its not working.... :(
thatnks for the help
here the problem is you didn't wrote the web.xml file.
i am writing here
<webapp>
<servlet>
<servlet-name>FirstServlet </servlet-name>
<servlet-class>FirstServlet </servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>FirstServlet ></servlet-name>
<url-pattern>/myservlet<url-pattern>
</servlet-mapping>
</webapp>
copy this file and save with name wex.xml and put this one in the under WEB-INF directory.
and then restart the server
now you type the url in the address bar as
http://localhost:80880/foo/myservlet.
i think it will work mostly.
ok bye,
babu.
If your folder structure is like this:
tomcat 5.5
webapps
- ServletTry
-- WEB-INF
--classes
-FirstServlet.class
then your web.xml file should be in the path:
tomcat 5.5\webapps\ServletTry\WEB-INF\
after restarting, try this link:
http://localhost:8080/ServeltTry/FirstServlet
if it still does not work, please post the error message that you get
and after restarting the server, you can access the servlet using:
Hi there!
I had also big problems to understand the structure and functions in Tomcat.
Uninstall your Apache Tomcat and install again, the go to this website:
http://www.coreservlets.com/Apache-Tomcat-Tutorial/#Test1
there are two things to do
1. make a directory, in <inst dir>\Tomcat 5.5\webapps\ROOT\WEB-INF\
classes
2. replace your original web.xml with his/hers modified web.xml.
And now you should be set to go!
Thanks to that great tutorial, Apache Tomcat was much easier to understand!
// LiPpE
