return decimal

> hey

> how can i rturn the fractional and the integral part

There are a variety of ways, from mathematical approaches to string manipulation. I'll bet if you search this forum and/or the web, you'll see that this question has been asked numerous times before. Try searching for this first; if you've tried something and it's not working out, post what you've tried and what it is you're confused about.

Good luck!

yawmarka at 2007-7-16 2:06:07 >

Like Learnable suggested:

double num = 321654.652;

double integral = (double)((int)num);

double fractional = num-integral;

.

I suspect a double-error-rounding-question next...

; )

prometheuzza at 2007-7-16 2:06:07 >

Or just use a String.

public class DoubleSeparation {

public DoubleSeparation() {

}

public static void main(String[] args)

{

double d = 321654.652;

String s = Double.toString(d);

int n = s.indexOf('.');

String c = s.substring(0, n);

String m = s.substring(n+1, s.length());

int in = Integer.parseInt(c);

int fr = Integer.parseInt(m);

System.out.println(in + " " + fr);

}

}

Learnablea at 2007-7-16 2:06:07 >

> Now try the same with "double d = 0.000001;"

>

> Hint: You will need DecimalFormat if you want to use

> Strings.

To preserve the representation of the mantissa, you will have to use either BigDecimal or DecimalFormat. The mantissa has to be represented by a String. Here is the implementation using BigDecimal.import java.math.*;

public class DoubleSeparation {

public DoubleSeparation() {

}

public static void main(String[] args)

{

BigDecimal b = new BigDecimal("0.00000001");

long c = b.longValue();

b = b.subtract(new BigDecimal(c));

int s = b.toString().length();

String m = "";

if(s >= 2)

m = b.toString().substring(2, s);

System.out.println(c + " " + m);

}

}

Learnablea at 2007-7-16 2:06:08 >