Hi All,
Please answer my question , i will explain it with example.
String txt = "nithEOoREOR nitho EOR";
From this string i need to extractnithEOoR
I need to get this from the group() of Matcher.
simply i need a pattern which get chacters before EOR
Thanks,
Kith
It sounds like you want either a reluctant quantifier or a positive lookahead or lookbehind.
The pattern for the reluctant quantifier would be like this, I think: String pattern = "(.+?)EOR"
Reluctant quantifiers are mentioned, but not explained, I think, in the Pattern API.
For the lookarounds, use google, or see http://www.regular-expressions.info/lookaround.html
http://www.regular-expressions.info/lookaround2.html
Thanks sabre150, you got that.
This is going with Grouping it seems.
Could u please explain the pattern
.* means any number of chacters . I am not familar with ?
And in your pattern why u put .* at the end
Is there any way to give scores to ur answer?:)
Thanks again.
Kith
You need to read the documentation. A forum is not the place to present all the theory on a topic.
For minimal information see the following code sample.
import java.util.regex.*;
public class Test5 {
// The content of the first pair (.*?) is group 1
// The ? is to make it a reluctant match becaue we want it
// to match as soon as possible..
// The final .* says anything can be after the first EOR
private static final Pattern pattern = Pattern.compile("(.*?)EOR.*");
public static void main(String[] args) {
try {
Matcher matcher = pattern.matcher("nithEOoREOR nitho EOR");
if (matcher.matches()) {
String theBitYouWant = matcher.group(1);
System.out.println(theBitYouWant);
}
} catch (Exception e) {
e.printStackTrace();
}
}
}