passing parameters from java to shell script

You cannot pass anything but int as an exit parameter. This is true for all kinds of programs (corrent me, if I'm wrong).

If you want to have a string from a program, the most simple way is to make the java program print this to the standard output, and get it with the shell. For example:

A dummy java class:

public class dummyout {

public static void main(String[] args) {

System.out.println("Output string");

}

}

And the shell script:

#!/bin/bash

RESULT=`java dummyout`

echo "Result is: $RESULT"

Hope this helps.

Lacek at 2007-7-4 23:56:05 >

What you have is quite different from what Lacel recommended. Do it exactly as suggested, probably adding "-classpath ${CLASSPATH}" between "java" and "dummyout"

When you write command such as:

RESULT=java -classpath ${CLASSPATH} dummyout

The shell interprets it as follows: Assign string "java' to shell variable "RESULT" and execute command "-classpath" with arguments "${CLASSPATH}" and "dummyout". Since "-classpath" is not a command you get the error. You should be glad, if there was command named "-classpath" it would have executed and you would have been even more confused.

When you do it as suggested:

RESULT=`java -classpath ${CLASSPATH} dummyout`

Then shell interprets it as: execute the command within back-quotes and assign its output(first word of the output actually, I think) to the shell variable RESULT. This is what you are looking for, Look at man pages of shell for more...

hth.;

hemalpandya at 2007-7-4 23:56:05 >

The below thing is working:

Shell script:

#!/bin/ksh

javac TestEnvVarSet.java

typeset VAR=`java TestEnvVarSet`

echo $VAR

echo "Done"

Java:

public class TestEnvVarSet {

public static void main(String args[]){

System.out.println("test string");

}

}

I am wondering is there any other approach for this. Thanks for all the help

Shyam

shyam29 at 2007-7-4 23:56:06 >