hi friends,
i have doubt
i have arry like this
String[] groups ={"Manager", "technical",programmer};
i have another string variable test = "manager", i want to check "manager" is contains inside the groups can any one suggest
like in oracle we have exists some this like this in java.
i want to check one string like "manager" exhists inside the group array.
thanks
use
matches(regex)
u r regex wiil be string that u want to match . I u r case it will be "manager"
> matches(regex)
> u r regex wiil be string that u want to match .
Which is not really a general rule. Equals is still simpler.
> Iterate and use equals...
Looks like he will need to use equalsIgnoreCase
thanks for the answer, but i dont want to use loop, the same thing is there any way to do it with vector ?
Instead of using string array is there any way to do it with vector ?
because i dont want to use loop
> thanks for the answer, but i dont want to use loop,
> the same thing is there any way to do it with vector ?
Why don't you want to use a loop? Odd requirement. Is this homework?
can u please write how to do this, sorry iam beginner to java programminmg
Vector V1 = new Vector();
V1.add("Manager");
V1.add("cleark");
V1.add("Manager");
V1.add("cleark");
Use this
> Store u r elements in vector by put()
Do not use Vectors. Old, slow, outdated. And pointless anyway - if theOP does not want to use a loop, he should add the elements to a Hashset, which does *exactly* what he needs without iterating.
but how to check weather a string eg:"manager" exhists using a vector
thanks
> but how to check weather a string eg:"manager"
> exhists using a vector
>
> thanks
Use a HashSet, just as Rene said. It's better in this case. Do also note that the "search" will be case sensitive.
Kaj
> Use contains(Obj) from vector
No. Never use Vectors if you don't have to, and use set.contains() to do in much less steps than with a list.
> Yes hASHsET BETTER THAN Vector
Everyhing is better than Vector. If you need a synchronized list, use Collections.synchronizedList(). If you don't need it synchronized: leave it altogether and use an arrayList or LinkedList or whetever suits you the most.
