A user would like to parse for:
name : status
value : passed
in the following string:
name : status
value : passed
name : status
value : operational
name : result
value : passed
In Perl, it would be: if ( str =~ /name : status\nvalue : passed/) { return true }
How would one do it in Java? Mind the '\n' (newline) at the end of each line.
if (str.indexOf("name : status\nvalue : passed") >= 0) return true;
You're absolutely right.
Now, let's alter it a little. What if the string consists of the following XML elements taken out of an XML file?
<output>
<name>status</name>
<value>passed</value>
</output>
How would you do in Java what this Perl code does? Pretend there are multiple spaces before each tag.
if (str =~ /<name>status</name>[\n\r]\s+<value>passed</value>/) return true;
Message was edited by:
bai13ys
Message was edited by:
bai13ys
whats stopping you from reading a regex tutorial or looking
up one of the many java xml parsers?
http://www.google.com/search?hl=en&safe=off&q=java+xml
Java XML parser is too complicated for parsing a simple name-value pair under the same parent. I don't want to use 20+ lines of code with which 10 of those being DOM document setup code. I'm pretty sure it's doable, though. I just think it's way too tedious for a simple thing like this.
Thanks, I missed the Matcher.find() method. That did the trick.
> if (str =~ /<name>status</name>[\n\r]\s+<value>passed</value>/) return true;
That's not valid even in Perl; you didn't escape the slashes in the end tags, and [\n\r]\s+ is redundant, since \s matches linefeed and carriage return. Anyway, in Java you would do something like this this: Pattern p = Pattern.compile("<name>status</name>\\s+<value>passed</value>");
Matcher m = p.matcher(str);
return m.find();
