Parsing XML
Well today is the firs today I'm working with XML in Java, and I managed to get pretty far [ in my opinion. ] However, I have seem to hit a stumbling block that I haven't been able to surmount.
I have a very basic XML document [ stats.xml ]
<?xml version='1.0' encoding='utf-8'?>
<stats>
<item>Sidewinder</item>
<item>11-45-88</item>
</stats>
And my Java code parses the xml and prints:
Sidewinder
11-45-88
To the console, however I want each element to be stored in a list / array and I haven't been able to figure out how to do that. Here is my code:
package test;
import java.io.*;
import javax.xml.parsers.*;
import org.w3c.dom.*;
publicclass ParseXML{
staticpublicvoid main(String[] arg){
try{
String xmlFile ="test/stats.xml";
File file =new File(xmlFile);
if(file.exists()){
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse(xmlFile);
NodeList list = doc.getElementsByTagName("*");
Element element = (Element)list.item(0);
System.out.println(element.getTextContent());
}else{
System.out.print("File not found!");
}
}catch (Exception e){
System.exit(1);
}
}
}
If anyone could help me, I would appreciate it.
Thank you.
> To the console, however I want each element to be
> stored in a list / array and I haven't been able to
> figure out how to do that.
Can u elaborate more on this? n by the way, lots n lots of dom example are available on the internet... check this out:
http://www.exampledepot.com/egs/org.w3c.dom/pkg.html
Well lets say this is my XML file:
<?xml version = "1.0" ?>
<Employee-Detail>
<Employee>
<Emp_Id> E-001 </Emp_Id>
<Emp_Name> Vinod </Emp_Name>
<Emp_E-mail> Vinod1@yahoo.com </Emp_E-mail>
</Employee>
</Employee-Detail>
The code above would print
E-001
Vinod
Vinod1@yahoo.com
To the console. I want each value to be stored in an array. ie)
value[0] = E-001
value[1] = Vinod
value[2] = Vinod1@yahoo.com
Obviously there needs to be a loop / iterator but the getTextContent method just returns every value in a single string and I don't know how to iterate through that.
Well I got a bit farther, managed to do what I want in my "test" file, however the real implementation will have hundreds of elements, and i really dont feel like having to use my code because I would have to write 3 lines of code for every element in my xml doc. Is there anyway I can make the endElement method into a loop so I dont have to statically add every element?
package xml;
import java.io.CharArrayWriter;
import java.io.FileReader;
import org.xml.sax.Attributes;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
import org.xml.sax.XMLReader;
import org.xml.sax.helpers.DefaultHandler;
import org.xml.sax.helpers.XMLReaderFactory;
public class parseXML extends DefaultHandler {
public static String[] stats = new String[50];
private static CharArrayWriter contents = new CharArrayWriter();
public void startElement( String namespaceURI, String localName, String qName, Attributes attr ) throws SAXException {
contents.reset();
}
public void endElement( String namespaceURI, String localName, String qName ) throws SAXException {
if ( localName.equals( "Emp_Id" ) ) {
stats[0] = contents.toString();
}
if ( localName.equals( "Emp_Name" ) ) {
stats[1] = contents.toString();
}
if ( localName.equals( "Emp_E-mail" ) ) {
stats[2] = contents.toString();
}
}
public void characters( char[] ch, int start, int length ) throws SAXException {
contents.write( ch, start, length );
}
public static void main( String[] argv ){
try {
XMLReader xr = XMLReaderFactory.createXMLReader();
parseXML pxml = new parseXML();
xr.setContentHandler( pxml );
xr.parse( new InputSource(new FileReader("doc.xml")));
for(int i = 0; i < 3; i++){
System.out.println( stats[i]);
}
}catch ( Exception e ) {
e.printStackTrace();
}
}
}
