How do you know when to use super?

> The only exception is when the parent class have an empty constructor.

If you do not supply a call to another constructor of the same class or a construtor of the parent class as the first statement of your constructor, an implicit call to the super class's default (no-arg) constructor is inserted by the compiler. Now if that implicitly invoked constructor does not exist or is not accessible, it is a compile-time error situation.

BIJ001a at 2007-7-13 0:22:16 >

Check the following sample:

public class B{

public B(){

System.out.println("B");

}

}

public class A extends B{

public A(){

System.out.println("A");

}

}

public class Test{

public static void main(String[] args){

A a = new A();

}

}

result:

B

A

surprised?

manuel.leiriaa at 2007-7-13 0:22:16 >