java struts2 xml

use a simple servlet to send xml data.

example 1

import java.io.BufferedInputStream;

import java.io.File;

import java.io.FileInputStream;

import java.io.IOException;

import javax.servlet.ServletException;

import javax.servlet.ServletOutputStream;

import javax.servlet.http.HttpServlet;

import javax.servlet.http.HttpServletRequest;

import javax.servlet.http.HttpServletResponse;

public class SendXml extends HttpServlet {

public void doGet(HttpServletRequest request, HttpServletResponse response)

throws ServletException, IOException {

//get the 'file' parameter

String fileName = (String) request.getParameter("file");

if (fileName == null || fileName.equals(""))

throw new ServletException(

"Invalid or non-existent file parameter in SendXml servlet.");

// add the .doc suffix if it doesn't already exist

if (fileName.indexOf(".xml") == -1)

fileName = fileName + ".xml";

String xmlDir = getServletContext().getInitParameter("xml-dir");

if (xmlDir == null || xmlDir.equals(""))

throw new ServletException(

"Invalid or non-existent xmlDir context-param.");

ServletOutputStream stream = null;

BufferedInputStream buf = null;

try {

stream = response.getOutputStream();

File xml = new File(xmlDir + "/" + fileName);

response.setContentType("text/xml");

response.addHeader("Content-Disposition", "attachment; filename="

+ fileName);

response.setContentLength((int) xml.length());

FileInputStream input = new FileInputStream(xml);

buf = new BufferedInputStream(input);

int readBytes = 0;

while ((readBytes = buf.read()) != -1)

stream.write(readBytes);

} catch (IOException ioe) {

throw new ServletException(ioe.getMessage());

} finally {

if (stream != null)

stream.close();

if (buf != null)

buf.close();

}

}

public void doPost(HttpServletRequest request, HttpServletResponse response)

throws ServletException, IOException {

doGet(request, response);

}

}

example 2

import java.io.BufferedInputStream;

import java.io.IOException;

import java.io.PrintWriter;

import java.net.MalformedURLException;

import java.net.URL;

import java.net.URLConnection;

import javax.servlet.ServletException;

import javax.servlet.http.HttpServlet;

import javax.servlet.http.HttpServletRequest;

import javax.servlet.http.HttpServletResponse;

public class ResourceServlet extends HttpServlet {

public void doGet(HttpServletRequest request, HttpServletResponse response)

throws ServletException, IOException {

//get web.xml for display by a servlet

String file = "/WEB-INF/web.xml";

URL url = null;

URLConnection urlConn = null;

PrintWriter out = null;

BufferedInputStream buf = null;

try {

out = response.getWriter();

url = getServletContext().getResource(file);

//set response header

response.setContentType("text/xml");

urlConn = url.openConnection();

//establish connection with URL presenting web.xml

urlConn.connect();

buf = new BufferedInputStream(urlConn.getInputStream());

int readBytes = 0;

while ((readBytes = buf.read()) != -1)

out.write(readBytes);

} catch (MalformedURLException mue) {

throw new ServletException(mue.getMessage());

} catch (IOException ioe) {

throw new ServletException(ioe.getMessage());

} finally {

if (out != null)

out.close();

if (buf != null)

buf.close();

}

}

public void doPost(HttpServletRequest request, HttpServletResponse response)

throws ServletException, IOException {

doGet(request, response);

}

}

Hope That Helps

java_2006a at 2007-7-12 20:35:44 >