class test{
publicstaticvoid main(String[] args){
String temp1 ="Me";
String temp2 ="Me";
System.out.println(temp1.equals(temp2));
}
}
I wrote the above quickly to test if temp1 and temp2 were objects. Well it appears that they are because I could use the equals
method. Is this just a shortcut in java, and exactly the same thing as writing
String temp1 =new String("Me");
?
> I wrote the above quickly to test if temp1 and temp2
> were objects. Well it appears that they are because I
> could use the equals
method.
temp1 and temp2 are variables whose values are references, not objects. They both refer to the same String object, because Java pools string literals.
> Is this
> just a shortcut in java, and exactly the same thing
> as writing
> String temp1 = new String("Me");
No. With the new String you're creating a new String object that's a copy of the one that's in the string pool. Without it--as in your first code--it just provides a reference to the existing String in the pool.
