validate string

OR

1) Check the length of the string by using the length() method, to make sure it does not exceed 8 characters.

Convert each character to it's ASCII value, then check it again the ASCII table.

>>>

for ( int i = 0; i < str.length(); i++ )

{

int char = str.charAt( i );

// the first check sees if it's between 0 and 9 the second if it's from A .. Z

if ( ( char >= 48 && <= 57 ) || ( char >= 65 && char <= 90 ) )

{

char is valid

}

else

{

char is invalid

}

}

Message was edited by:

bryano

bryanoa at 2007-7-12 19:44:50 >

> > You could use the regex special character

> \w

> > that matches a word(alphanumeric) character (same

> as

> > [a-zA-Z_0-9]).

> >

> > Regex example:

> > /^\w{0,8}$/

>

> Those slashes won't work in Java's regex. Since

> you're matching the entire String, you don't need to

> specify the start and end of the String with the ^

> and $ signs. And the OP did not mention the character

> class [a-z], so I'd say this regex should do:

> [A-Z|0-9]{1,8}

I never used regex in java.

Does \w{1,8} work? (if I need the class [a-z])

Bruno_Grassellia at 2007-7-12 19:44:50 >

> Yep, try running this:

> System.out.println("aBC46".matches("\\w{1,8}"));

> // you need to escape the \ in the String

I tried and it works.

public class RegEx {

public static void main (String args[]){

System.out.println("aBC46".matches("\\w{1,8}"));

System.out.println("aBC46*".matches("\\w{1,8}"));

}

}

I will read more about java regular expressions, I only know about javascript regular expressions.

Thanks for help and sorry for making a question in this topic.

Bruno_Grassellia at 2007-7-12 19:44:50 >