How to distinguish between two elements with the same name in XML file

> > With the given coding only could someone please

> tell

> > me the solution for my problem.

>

> um.... if the given coding worked.... you wouldn't

> need another solution? I think the poster above

> (ejp) has suggested a valid suggestion. Why not

> implement it?

Exactly. If 'the given coding only' worked, you would already have a solution, you wouldn't have a problem, and you wouldn't be posting this question.

You have to change your 'given coding' somehow. For a start , as you need to detect context, you will have to consider more than one line at a time, which throws out your present method signature. Much the easiest way to do that is to use XPath, as I already said. If you want to do it some other, harder, way, good luck.

ejpa at 2007-7-12 19:19:22 >

I hope this is what you suggested me to do

public String ProdCitLine(String line)

{

char cc='A';

int num=1;

Pattern p = Pattern.compile("(<product>00000000)?<citation citation-type=\".*?\" id=\"\">");

Matcher m = p.matcher(line);

while (m.find())

{

if (m.start(1) != -1)

{

// it has a <product> parent

for(Matcher RegexMatcher1 = p.matcher(line); RegexMatcher1.find();)

{

String chkEntity1 = RegexMatcher1.group();

int lastIndex = chkEntity1.lastIndexOf("\">");

String subchkEntity1=chkEntity1.substring(0,lastIndex);

line = line.replaceFirst(chkEntity1,subchkEntity1+"ref00"+cc+"\">");

cc++;

}

}

else

{

// it doesn't

for(Matcher RegexMatcher2 = p.matcher(line); RegexMatcher2.find();)

{

String chkEntity2 = RegexMatcher2.group();

int lastIndex = chkEntity2.lastIndexOf("\">");

String subchkEntity2=chkEntity2.substring(0,lastIndex);

line = line.replaceFirst(chkEntity2,subchkEntity2+"ref00"+num+"\">");

num++;

}

}

}

return line;

}

My output is

<?xml version="1.0" encoding="UTF-8"?>

<!DOCTYPE article SYSTEM "ABC.dtd">

<article xmlns="XYZ">

<front>

<product>

<citation citation-type="book" id="ref00A">

</citation>

</product>

<product>

<citation citation-type="book" id="ref00B">

</citation>

</product>

</front>

<ref-list>

<title>REFERENCES</title>

<citation citation-type="book" id="ref00C">

<citation citation-type="book" id="ref00D">

</citation>

</ref-list>

</article>

But I need my XML output as

<?xml version="1.0" encoding="UTF-8"?>

<!DOCTYPE article SYSTEM "ABC.dtd">

<article xmlns="XYZ">

<front>

<product>

<citation citation-type="book" id="ref00A">

</citation>

</product>

<product>

<citation citation-type="book" id="ref00B">

</citation>

</product>

</front>

<ref-list>

<title>REFERENCES</title>

<citation citation-type="book" id="ref001">

<citation citation-type="book" id="ref002">

</citation>

</ref-list>

</article>

sony_tja at 2007-7-12 19:19:22 >