HI, how would I call this method from main? help pls

> whoops, sorry..

>

> i am trying to call it out in main, but i get errors

> using

>

> writeArray(str, anArray);

It's because str and anArray don't exist in the main method.

String myString = "asdf";

char[] myCharArray = new char[6];

writeArray(myString, myCharArray);

Also, what is the point of passing a char array to the writeArray() method if you are just going to change it?

CaptainMorgan08a at 2007-7-12 20:40:03 >

import java.io.*;

public class FileArray {

static void writeArray(String str, char[]anArray) throws IOException{

anArray[0] = 'a';

anArray[1] = 'b';

anArray[2] = 'c';

anArray[3] = 'd';

anArray[4] = 'e';

anArray[5] = 'f';

str = "temp.txt";

DataOutputStream output = new DataOutputStream(new FileOutputStream(str));

for(int i=0; i <anArray.length; i++)

output.writeChar(anArray[i]);

output.close();

}

public static void main(String[] args) throws IOException {

writeArray(str, anArray);

}

}

Why are you passing a char array if you change it?

You will get NullPointerExceptions if you use this code how it is.

Problems would arise from the char array. If you pass in a char array of length 2, how could you modify the elements at 2, 3, 4 and 5?

Below that, you have a for statement. You should code something similar for the area where you assign values to anArray[0] to [5].

Or you could just not require a char array as a parameter at all, seeing as you're just overwriting it. You'd need to define it within the method though, because right now it's being defined as a parameter.>

LukeFossa at 2007-7-12 20:40:03 >