Transform using XSL 2.0 with JAXP

Hi,

I am transforming a xml file to a jsp using xsl. I am shifting from xsl 1.0 to 2.0.

I tried to use the "character-maps" functionality available in xsl "2.0".

I expected the below xsl code:

<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions" xmlns:xdt="http://www.w3.org/2005/xpath-datatypes">

<xsl:output method="html" encoding="UTF-16" indent="yes" use-character-maps="cMaps"/>

<xsl:character-map name="cMaps">

<xsl:output-character character="? string="&lt;%"/>

<xsl:output-character character="? string="%&gt;"/>

</xsl:character-map>

<xsl:template match="/">

<xsl:text>?lt;/xsl:text>

</xsl:template>

</xsl:stylesheet>

To generate the following:

<% %>

The expected transformation of character-maps does not work when I use "javax.xml.transform" package for transformation.

Following is the piece of code which I use for transformation

try {

javax.xml.transform.TransformerFactory tFactory = javax.xml.transform.TransformerFactory.newInstance();

javax.xml.transform.Transformer transformer = tFactory.newTransformer(stXsl);

transformer.transform(stInput, srOutput);

catch (Exception ex) {

}

The above transformation generates?/i>

The xsl seems to be correct as I get the expected output when I use XML Spy.

Do I need to something more in my java code for using xsl 2.0.

Regards

Anup

[1737 byte] By [akallia] at [2007-11-27 7:02:52]