Hi,
In a Linux environment I can just go
date '+%s'
to get the seconds since epoc ... how do I get that value
in Solaris (any version, really)? It appears that strftime
on Solaris knows nothing about epoc, so I can't trivially
get date to display the value.
Cheers
thanks cloaks and Darren - I didn't mean to use perl, hence the
question about date (or a 'simple' sh solution'). Even though we
do use perl (and I use it quite happily myself) the preference
would be to avoid it - more staff here know sh (and the varied
unix tools) than perl.
Sorry for the late response!
Cheers
I'm surprised there is no apparent way of doing this in Solaris, your two best options are to use perl or write a small script/c-program which you call 'epoch'.
Two other ways of getting the epoch;
nawk 'BEGIN { print srand()}'
/usr/bin/truss /usr/bin/date 2>&1 | /usr/bin/awk '/^time/ {print $NF}'
You can always call perl in a shell script, i think the lines
#!/bin/sh
epoch=`perl -le 'print time'`
echo "$epoch"
is quite understandable to anyone who knows a bit of scripting..
.7/M.
