How to find integer in String

> take a look as the isDigit method in the Character

> class.

>

> > Character.isDigit(str.charAt(index))

>

>

> if you do this in a loop and then break out when you

> hit a non-digit. You can then substring based on a

> count you incremented in the loop.

>

> EDIT: I need glasses. No loops

>

> Message was edited by:

> _helloWorld_

His homework assignment explicitly disallows looping

georgemca at 2007-7-12 15:31:30 >

> With these conditionsit's easiest to use

> java.text.NumberFormat.import java.text.*;

> ...

> fmt=NumberFormat.getInstance();

> print(fmt.parse("1234hi")); // 1234

^^I never thought of that, I did think of this however.

public class Example {

static int index;

public static void main(String[] args) {

System.out.println(getNumbers("123xx"));

}

static String getNumbers(String s ) {

if(Character.isDigit(s.charAt(index))) {

index++;

getNumbers(s);

}

return s.substring(0, index);

}

}

_helloWorld_a at 2007-7-12 15:31:30 >

Hi,

without iterator, i don't think it is possible.

try this one

String str="123hi";

String val="";

for(int i=0;i<str.length();i++)

{

if(Character.isDigit(str.charAt(i)))

val=val+str.charAt(i);

}

thn convert this string into integer.>

RAMJANEa at 2007-7-12 15:31:30 >