Process exit value
Hi,
Does anyone know what exit value of 18 mean? I was calling Runtime.exec() to execute an external program and a call to a waitFor() method returned a value of 18. How do I find out what this means? I am running this under windows XP. The code normally works fine, in fact this was the first time that I saw it returning error code other than 0. This happened several times yesterday but running it today seems to be OK again... Any help will be greatly appreciated...
[483 byte] By [
seek123a] at [2007-11-27 5:11:15]
It depends on the process itself. I think there may be certain informal standards, but you'd have to read the docs for the particular program you're running. In a unix environment, you'd usually look at the man pages for that. I don't know what the Windows equivalent docs would be.
jverda at 2007-7-12 10:31:33 >
> thats a windows question. and its better answered by
> google.
>
> http://www.google.com/search?hl=en&q=windows+%22exit+c
> odes%22
>
> http://www.hiteksoftware.com/knowledge/articles/049.ht
> m
> 18 There are no more files.
Um, yeah. What he said.
(Faster than I *and* a more useful answer. Bloody kids these days.)
jverda at 2007-7-12 10:31:33 >
