reading a keyboard text input character by character
Hello,
can anyone give me help with reading a string (inputed from the keyboard) character by character?
I am just starting this code so i dont have any code atm.
i just need some pointers about how to go about reading character by character.
edit: i dont think i am clear enough.
I wish to read a string. and then character by character find out if the character is a vowel, constanant or a space. and then also count the number of characters
Any help will be greatly appriciated. thanks
Hypercondor
Message was edited by:
Hypercondor
String a="text";char[] tabC = a.toCharArray() ;for(int j=0;j<tabC.length ;j++){//process with chars}RegardsMarecki>
Try this code :
import java.util.Scanner;
public class ReadDemo {
static char[] vowel={'a', 'e', 'i', 'u', 'o', 'w', 'y'};
public static void main(String[] args) {
System.out.println("Enter a word:");
Scanner scanner = new Scanner(System.in);
String word = scanner.next();
System.out.println("Entered Word: "+word);
System.out.println("# of characters: "+word.length());
System.out.println("# of vowels: "+countVowels(word));
}
static int countVowels(String s){
char[] array = s.toCharArray();
int counter=0;
for (int i = 0; i < array.length; i++) {
if(isVowel(array[i])){
counter++;
}
}
return counter;
}
static boolean isVowel(char c){
for (int i = 0; i < vowel.length; i++) {
if(c==vowel[i]){
return true;
}
}
return false;
}
}
If i put the text into array. say i had "hello my name is hypercondor". Would that not put all the text into one section of the array and not split it up?Regards hypercondor
import java.util.Scanner;
public class ReadDemo {
static char[] vowel={'a', 'e', 'i', 'u', 'o', 'w', 'y'};
public static void main(String[] args) {
System.out.println("Enter a word:");
Scanner scanner = new Scanner(System.in);
String word = scanner.next();
System.out.println("Entered Word: "+word);
System.out.println("# of characters: "+word.length());
System.out.println("# of vowels: "+countVowels(word));
}
static int countVowels(String s){
char[] array = s.toCharArray();
int counter=0;
for (int i = 0; i < array.length; i++) {
if(isVowel(array[i])){
counter++;
}
}
return counter;
}
static boolean isVowel(char c){
for (int i = 0; i < vowel.length; i++) {
if(c==vowel[i]){
return true;
}
}
return false;
}
}
Thank you very much for this. Alot more than i asked for. Although i need to be able input more than one word. Also would i have to use the Hex code to make it check for spaces?
Anymore help would be greatly appriciated.
Try this:
import java.util.Scanner;
public class ReadDemo {
static char[] vowel={'a', 'e', 'i', 'u', 'o', 'w', 'y'};
public static void main(String[] args) {
System.out.println("Enter a word:");
Scanner scanner = new Scanner(System.in);
String word = scanner.nextLine();////////////////////////CHANGE HERE
System.out.println("Entered Word: "+word);
System.out.println("# of characters: "+word.length());
System.out.println("# of vowels: "+countVowels(word));
System.out.println("# of spaces: "+countSpaces(word));
}
static int countSpaces(String s){
return s.split(" ").length;
}
static int countVowels(String s){
char[] array = s.toCharArray();
int counter=0;
for (int i = 0; i < array.length; i++) {
if(isVowel(array[i])){
counter++;
}
}
return counter;
}
static boolean isVowel(char c){
for (int i = 0; i < vowel.length; i++) {
if(c==vowel[i]){
return true;
}
}
return false;
}
}
in order to count spaces, use this instead:
static int countSpaces(String s){
int count=0;
char[]a=s.toCharArray();
for (int i = 0; i < a.length; i++) {
if(32==(int)a[i]){ //32 = (int)' '
count++;
}
}
return count;
}
Thank you so much. Truely you are a legend.
This is my code at the moment.
import java.util.Scanner;
public class ReadDemo
{
static char[] vowel={'a', 'e', 'i', 'u', 'o', 'w', 'y'};
public static void main(String[] args)
{
System.out.println("Enter a word:");
Scanner scanner = new Scanner(System.in);
String text = scanner.nextLine();
System.out.println("Entered Text: "+text);
System.out.println("# of characters: "+text.length());
System.out.println("# of vowels: "+countVowels(text));
System.out.println("# of constanants: "+(text.length()-countVowels(text)-countSpaces(text)));
System.out.println("# of spaces: "+countSpaces(text));
}
static int countVowels(String s)
{
char[] array = s.toCharArray();
int counter=0;
for (int i = 0; i < array.length; i++)
{
if(isVowel(array[i])){
counter++;
}
}
return counter;
}
static boolean isVowel(char c)
{
for (int i = 0; i < vowel.length; i++)
{
if(c==vowel[i])
{
return true;
}
}
return false;
}
static int countSpaces(String s){
int count=0;
char[]a=s.toCharArray();
for (int i = 0; i < a.length; i++) {
if(32==(int)a[i]){ //32 = (int) for a ' '
count++;
}
}
return count;
}
}
Now all i gotta do is make a list of the frequency with which each vowel appears in the string as a percentage of the number of printing characters. I think i need a array to do this. also i need to limit the input length to 300 characters.
static int countSpaces(String s)
{
int count=0; // Counter set to 0
char[]a=s.toCharArray();
for (int i = 0; i < a.length; i++)
{
if(32==(int)a[i]){ //32 = (int) for a ' '
count++; // count + 1
}
}
return count;
I understand the majority of this code. But am not completely certain how it realises its a space. I understand that 32 is the integer value for a space. but i dont understand how Java knows its the integer for a space.
As always having the code is great. But it has to be backed up with knowledge. Could you please explain.
Regards
Hyper.
Run this example:
public static void main(String[] args){
for(int i=0; i<255; i++){
System.out.println(i+"->"+(char)i);
}
}
this will list the first 255 characters with their decimal code.
you can also do this:
public static void main(String[] args){
int i=32;//decimal code for simple space : ' '
System.out.println(i+"->"+(char)i);
}
Hope that helps!
Thank you very much for the help. I have one more question.
could you describe what this means please?
char[]a=s.toCharArray();
within
static int countSpaces(String s){
int count=0;
char[]a=s.toCharArray();
for (int i = 0; i < a.length; i++) {
if(32==(int)a[i]){ //32 = (int)' '
count++;
}
}
return count;
}
char[]a=s.toCharArray();
this creates a characters array of the string s.
Example:
String s = "abc";
char[] a = s.toCharArray();//or char a[] =s.toCharArray(); //a = {'a', 'b', 'c'}
for(int i=0; i<s.length, i++){
System.out.println(a[i]);
}
results:
a
b
c
Hope That helps>
