Finding the smallest value from an array
Hi there :)
I started learning Java a few days ago and have now run into my first problem :p
I am using Netbeans on Mac OS X.
I need to find the smallest value from an array. So far I've had no luck. Any suggestions would be fantastic.
The code so far:
/*
* Math Problems
*
* Created on May 4, 2007, 10:54 AM
*
* PROJECT 1: - IN PROGRESS
* Create a program that allows you to create an integer array of 18 elements with the following values
* 3, 2, 4, 5, 6, 4, 5, 7, 3, 2, 3, 4, 7, 1, 2, 0, 0, 0
*
* - The program computes the sum of elements 0 to 14 and stores it in element 15// COMPLETED
* - The program computes the average and stores it in element 16 // COMPLETED
* - The program finds the smallest value from the array and stores it in element 17
*
* PROJECT 2: - TO DO
* Write a program that accepts from the command line and prints them out. Then use a for loop to print
* the next 13 numbers in the sequence where each number is the sum of the previous two. FOR EXAMPLE:
*
* - input>java prob2 1 3
* - output>1 3 4 7 11 18 29 47 76 123 322 521 843 1364
*
* PROJECT 3: - TO DO
* Write a program that accepts from the command line two numbers in the range from 1 to 40. It then
* compares these numbers against a single dimension array of five integer elements ranging in value
* from 1 to 40. The program displays the message BINGO if the two inputted values are found in the array
* element. FOR EXAMPLE:
*
* - input>java prob3 3 29
* - output>Your first number was 3
* -Your second number was 29
* -Its Bingo! // This message if 3 and 29 are found in the array
* -Bokya!// This message if 3 and 29 are not found in the array
* -The array was 7 5 25 5 19 30
*
* PROJECT 3 EXTENSION: - OPTIONAL
* Generate the array of 5 unique integers using random numbers
*
*/
package mathproblems;
/**
*
* @author Mohammad Ali
*/
publicclass Main{
/** Creates a new instance of Main */
public Main(){
}
/**
* @param args the command line arguments
*/
publicstaticvoid main(String[] args){
int A[]={3,2,4,5,6,4,5,7,3,2,3,4,7,1,2,0,0,0};
int O = A.length - 3;
int B = A[0] + A[1] + A[2] + A[3] + A[4] + A[5] + A[6] + A[7] + A[8] + A[9] + A[10] + A[11] + A[12] + A[13] + A[14];
A[15] = B;// Stores the sum of the integers in A[15]
int C = B / O;
A[16] = C;// Computes and stores the average in A[16]
int D = 101;
if (A[0] < A[1]){ D = A[0];}
else{ D = A[1];}
if (A[1] < A[2]){ D = A[1];}
else{ D = A[2];}
System.out.println("There are " + O +" numbers in the Array");
System.out.println("Those numbers add up to " + B +".");
System.out.println("The average of those numbers is " + C +".");
System.out.println("The smallest value in the array is " + D +".");
}
}
The code is incomplete, but it works so far. The problem is I know there must be an easier way. SAVE ME :)
[4607 byte] By [
Tritocha] at [2007-11-27 3:20:49]
> if (A[0] < A[1]) { D = A[0]; }
> else { D = A[1]; }
> if (A[1] < A[2]) { D = A[1]; }
> else { D = A[2]; }
Don't you meanif (A[0] < A[1]) { D = A[0]; }
else { D = A[1]; }
if (A[2] < D) { D = A[2]; }
if (A[3] < D) { D = A[3]; }
if (A[4] < D) { D = A[4]; }
// etc
A[17] = D;
But, please, longer (descriptive) variable
names - count, average, min etc. And it's usual (to the point of
being a rule) that variable names start with a lowercase letter.
Have you heard about loops? If not have a read of
http://java.sun.com/docs/books/tutorial/java/nutsandbolts/for.html
(and nearby pages) for an Easier Way.
I'd try something like that:int A[]={3,2,4,5,6,4,5,7,3,2,3,4,7,1,2,0,0,0};
Arrays.sort(A);
System.out.println("Smallest is: " + A[0]);
int num = A.length;
System.out.println("Number of values is: " + num);
int sum = 0;
for (int i = 0; i < A.length; i++) {
sum+=A[i];
}
System.out.println("Sum of values is: " + sum);
double d = (double)sum/num;
System.out.println("Average of values is: " + d);
@pbrockway2: Sorry for spoon feeding.
Hope this helps...
public class Minimum {
public static void main(String[] args) {
int[] arr={12,32,22,4,51,61,71,82,93,12};
int len = arr.length;
System.out.println("Length of array:"+len);
for (int i = 0; i < arr.length-1; i++) {
if(arr< arr[i+1]){
arr[i+1]=arr;
}else{
arr[i+1]=arr[i+1];
}
}
System.out.println("Minimum:"+arr[9]);
}
}
This code gives u the smallest number in the array:
int num[] = {10,23,2,45,64,32,14,6,9,110};
int temp = 0;
for(int i=0 ; i<num.length ; i++) {
for(int j=i ; j><num.length ; j++) {
if(num >= num[j]) {
temp = num;
num = num[j];
num[j] = temp;
}
}
}
System.out.println("The Smallest Number in the Array is : "+ num[0]);
Check out the [url= http://forum.java.sun.com/help.jspa?sec=formatting]tips and secret java codes[/url] for making your posts formatted.
Wow. Thanks a lot for the very fast responses :)I think a for loop appeals to me. Thank you all for the help. I think I'll use PhHein's code as it seems to be the smallest, yet, easier to understand.Thank you.
OK :)
Just thought I should show you the output as to help anyone else with the same problem:
/*
* Math Problems
*
* Created on May 4, 2007, 10:54 AM
*
* PROJECT 1: - IN PROGRESS
* Create a program that allows you to create an integer array of 18 elements with the following values
* 3, 2, 4, 5, 6, 4, 5, 7, 3, 2, 3, 4, 7, 1, 2, 0, 0, 0
*
* - The program computes the sum of elements 0 to 14 and stores it in element 15// COMPLETED
* - The program computes the average and stores it in element 16 // COMPLETED
* - The program finds the smallest value from the array and stores it in element 17// COMPLETED
*
* PROJECT 2: - TO DO
* Write a program that accepts from the command line and prints them out. Then use a for loop to print
* the next 13 numbers in the sequence where each number is the sum of the previous two. FOR EXAMPLE:
*
* - input>java prob2 1 3
* - output>1 3 4 7 11 18 29 47 76 123 322 521 843 1364
*
* PROJECT 3: - TO DO
* Write a program that accepts from the command line two numbers in the range from 1 to 40. It then
* compares these numbers against a single dimension array of five integer elements ranging in value
* from 1 to 40. The program displays the message BINGO if the two inputted values are found in the array
* element. FOR EXAMPLE:
*
* - input>java prob3 3 29
* - output>Your first number was 3
* -Your second number was 29
* -Its Bingo! // This message if 3 and 29 are found in the array
* -Bokya!// This message if 3 and 29 are not found in the array
* -The array was 7 5 25 5 19 30
*
* PROJECT 3 EXTENSION: - OPTIONAL
* Generate the array of 5 unique integers using random numbers
*
*/
package mathproblems;
/**
*
* @author Mohammad Ali
*/
import java.util.Arrays;
public class Main {
/** Creates a new instance of Main */
public Main() {
}
/**
* @param args the command line arguments
*/
public static void main(String[] args) {
int A[]={3,2,4,5,6,4,5,7,3,2,3,4,7,1,2,0,0,0};
Arrays.sort(A);
System.out.println("The smallest value in the array is " + A[0] + ".");
int num = A.length;
System.out.println("There are " + num + " values in the Array.");
int sum = 0;
for (int i = 0; i < A.length; i++) {
sum+=A[i];
}
System.out.println("Those numbers add up to " + sum + ".");
double d = (double)sum/num;
System.out.println("The average value of those numbers is " + d + ".");
}
What Iearned:
1) How to create for loops properly
2) How to import java.util.Arrays ( =D )
3) How to get a more accurate average using double instead of int
4) This forum is the best and has very helpful people 24/7 ( =D)
Thanks Again,
Mo.
Just a little point:* Project 1 also asked you to store the
results of the calculation back in the array. "A[15]=sum;"
and so on. You are going to have to deal with the fact
that a java array of ints can't have a double in it! It might
be worth documenting what value A[16] really ends up
with.
* My new designation requires a quota of such things; but
more importantly I'd hate you to lose marks...
> * - The program finds the smallest value from the array and stores it in element 17
> int A[]={3,2,4,5,6,4,5,7,3,2,3,4,7,1,2,0,0,0};
> Arrays.sort(A);
> System.out.println("The smallest value in the array is " + A[0] + ".");
They probably wanted you to find the minimum from (the original) elements 0 through 14, right? Since that's the question they asked with regards to the sum?
This can probably be argued either way, but I think the directions are ill-written.
