totally lost...
hey y'all!
so, i have this assignment in my computer science I class and i've done a good bit of it! however, i don't know if what i've done is right...and i'm totally lost in how to finish it. i've been working on it for a few days...looking all over the internet...i just don't feel like i know java well enough yet to adapt the info to what i need...any help with this will be much appreciated! y'all have a great day! - andrea
so, here's what i have so far with the assignment instructions there!
/*
This program will contain 10 elements of type integer. Each even numbered element will be equal to the square of a random number between 1 and 10. Each odd numbered element will be equal to the cube of a random number between 1 and 10. Element number zero is considered even for our purposes. This program will do the following:
1. print out the array
2. print the array in reverse order
3. find the maximum number in the array and its location
4. find the minimum number in the array and its location
5. sort the array in descending order
6. find another random number between 1 and 10, determine its square and determine how many times the number occurs in the array (if any).
*/
public class ArrayListTester
{
public static void main (String [] args)
{
int i,j;
int[] data1 = new int[10];
int[] data2 = new int[10];
for (i = 0; i < data1.length; i++)
data1 = i*i;
/* 1. print out the array */
System.out.println("Original array: ");
for(i = 0; i < data2.length; i++)
System.out.print(data1 + " ");
System.out.println("Reverse copy data1 to data2.");
if(data2.length >= data1.length)
for(i = 0, j = data2.length-1; i < data1.length; i++, j--)
data2[j] = data1;
/* 2. print the array in reverse order */
System.out.println("Reversed array: ");
for(i = 0; i < data2.length; i++)
System.out.print(data2 + " ");
}
/* 3. find the maximum number in the array and its location
4. find the minimum number in the array and its location */
public static int max(int[] t)
{
int maximum = t[0];
for (int i = 1; i < t.length; i++)
{
if (t > maximum)
{
maximum = t;
}
}
return maximum;
}
public static int min(int[] t)
{
int minimum = t[0];
for (int i = 1; i > t.length; i++)
{
if (t < minimum)
{
minimum = t;
}
}
return minimum;
}
}
/* 5. sort the array in descending order */
/* 6. find another random number between 1 and 10, determine its square and determine how many times the number occurs in the array (if any). */
ps. none of my formatting stayed like i have it...ugh...sorry!
[2959 byte] By [
colesa] at [2007-11-27 2:31:45]
Ok because I'm feeling generous today I'm going to get you started.
public class InvolvedExample
{
public static void main(String[] args)
{
// First off let's make an array of ints with 10 elements
int[] intArray = new int[10] ;
int x ; // An int to hold our seed value
Random r = new Random() ;// A randomizer to generate the next random number
StringBuffer buffer = new StringBuffer("intArray[") ;// A place to build a string representation of the array
// Now we'll spin through the array and set its values
for(int i=0; i<intArray.length; i++)
{
x = r.nextInt(10) + 1 ; // Generate the next random number between 1 and 10 inclusive
// Determine if the index of the array is even or odd (not the most graceful code but it works.
if(i % 2 == 0)
{
intArray[i] = (int) Math.pow(x, 2) ;
}
else
{
intArray[i] = (int) Math.pow(x, 3) ;
}
buffer.append(intArray[i]) ;
if(i><(intArray.length-1)){
buffer.append(", ") ;
}
}
buffer.append("]") ;
System.out.println(buffer) ;
}
}
Here's how to build your array (You only need one) The sorting and getting the max and min and finding a number in the array I leave for you to figure out.
Hope this helps,
PS.
sorry. i'm wayyy new to this whole forum thing...i've never done it. i just wanted some feedback on if
what i have is correct and then how to finish my assignment. i can't figure out how to sort in
descending order and i have no idea how to start #6. thanks again for your generous help!!!
/*
This program will contain 10 elements of type integer. Each even numbered element will be equal to
the square of a random number between 1 and 10. Each odd numbered element will be equal to the
cube of a random number between 1 and 10. Element number zero is considered even for our
purposes. This program will do the following:
1. print out the array
2. print the array in reverse order
3. find the maximum number in the array and its location
4. find the minimum number in the array and its location
5. sort the array in descending order
6. find another random number between 1 and 10, determine its square and determine how many times the number occurs in the array (if any).
*/
public class ArrayListTester
{
public static void main (String [] args)
{
int i,j;
int[] data1 = new int[10];
int[] data2 = new int[10];
for (i = 0; i < data1.length; i++)
data1 = i*i;
/* 1. print out the array */
System.out.println("Original array: ");
for(i = 0; i < data2.length; i++)
System.out.print(data1 + " ");
System.out.println("Reverse copy data1 to data2.");
if(data2.length >= data1.length)
for(i = 0, j = data2.length-1; i < data1.length; i++, j--)
data2[j] = data1;
/* 2. print the array in reverse order */
System.out.println("Reversed array: ");
for(i = 0; i < data2.length; i++)
System.out.print(data2 + " ");
}
/* 3. find the maximum number in the array and its location
4. find the minimum number in the array and its location */
public static int max(int[] t)
{
int maximum = t[0];
for (int i = 1; i < t.length; i++)
{
if (t > maximum)
{
maximum = t;
}
}
return maximum;
}
public static int min(int[] t)
{
int minimum = t[0];
for (int i = 1; i > t.length; i++)
{
if (t < minimum)
{
minimum = t;
}
}
return minimum;
}
}
/* 5. sort the array in descending order */
/* 6. find another random number between 1 and 10, determine its square and determine how many times the number occurs in the array (if any). */
