SetParameter and xslt
Hi all,
i've a made a class that pass parameter to an xsl with
transformer.setParameter("myparam","A/B/C")
Note that i want that the parameter was an XPATH to access node C in xml file.
Now, in my xsl i've declared the param:
<xsl:param name="myparam" />
but when i do
<xsl:value-of select="$myparam" />
i obtain A/B/C, and not the content of node identified by xpath A/B/C
What i wrong?
THX everybody in advance
[494 byte] By [
a12a] at [2007-11-27 3:34:39]

# 1
> Hi all,
>
> i've a made a class that pass parameter to an xsl
> with
>
> transformer.setParameter("myparam","A/B/C")
>
> Note that i want that the parameter was an XPATH to
> access node C in xml file.
> Now, in my xsl i've declared the param:
>
> <xsl:param name="myparam" />
>
> but when i do
>
> <xsl:value-of select="$myparam" />
>
> i obtain A/B/C, and not the content of node
> identified by xpath A/B/C
>
> What i wrong?
>
> THX everybody in advance
transformer.setParameter("myparam","A/B/C")
you are NOT setting a node object in the parameter, but rather the string "A/B/C".