How would I parse a String like this :
"CW5188>APRS,TCPXX*,qAX,T2WXCWOP2:@300244z3506.97N/11826.90W_281/007g009t051r000P000p000h16b10052v8"
into something like this :
String call ="CW5188";
String Mode ="APRS,TCPXX*,qAX,";
String location ="300244z3506.97N/11826.90W"
etc....
?
Those aren't rules, those are hints - I know I can't figure out what you want to do.
Try again - given your example string, tell us what maps to each of your %x entries. And how do you know when something is a delimiter and when its part of the next/previous entry?
If you can't describe the problem well enough for a random human to figure out what you're trying to accomplish, you certainly won't be able to write code for it.
Grant
"CW5188>APRS,TCPXX*,qAX,T2WXCWOP2:@300244z
3506.97N/11826.90W_281/007g009t051r000P000p000h16b1005
2v8"
into something like this :
String call = "CW5188";String Mode = "APRS,TCPXX*,qAX,";
String location = "300244z3506.97N/11826.90W"
etc....
?It looks like your rules MIGHT be:
call is everything before the '>'
Mode is the next three strings (separated by commas)
Location is everything between the '@' and '_'
Would that be correct?
I don't know about you, but I didn't learn Java to
become a dentist and pull teeth.
If the original poster can't be clear, why should
anyone even bother to help?
:-) Having spent many years interfacing with clients who have a very clear understanding of what they want but cannot even make a start at expressing what they want I think I am well qualified to be a dentist.
I don't know about you, but I didn't learn Java to
become a dentist and pull teeth.
If the original poster can't be clear, why should
anyone even bother to help?
The @OP was clear - they wanted to know how to parse the string. They even gave the results of the parse. Can't get much clearer than that. ;-)
Sometimes people just need to be pointed in the right direction.
"CW5188>APRS,TCPXX*,qAX,T2WXCWOP2:@300244z3506.97N/118
26.90W_281/007g009t051r000P000p000h16b10052v8"
%s%s%f%f%d%d%d%d%d%d%d%d%d%d
%s = string
%d = int
%f = float
the delimeters would be : (Space-Seperated)
> , : @ z g t r P h b v
I don't know about you, but I didn't learn Java to
become a dentist and pull teeth.
If the original poster can't be clear, why should
anyone even bother to help?
It's Friday, so it is a way to pass the time until the beer arrives?
There is no common delimiter in the String and even if i was a CSV file then conformation would still be required in most professional environments. Only a smart as would rush in.
Never mind, I found A way how to parse it
import java.util.*;public class SampleStringParser
{
char[] charAry;
public SampleStringParser(String toParse)
{
charAry = new char[toParse.length()];
char[] characters = toParse.toCharArray();
for(int i = 0; i < characters.length; i++)
{
charAry<i> = characters<i>;
}
}
public String parse(String s)
{
String parseable = new String(charAry);
int index = parseable.indexOf(s);
if(index == -1) return null;
char[] temp = charAry;
charAry = new char[temp.length- index];
for(int i = index + 1, b =0; i < temp.length; i++, b++)
{
charAry<b> = temp<i>;
}
return parseable.substring(0 ,index);
}
public static String[] APRSDataParse(String APRS)
{
SampleStringParser ssp =
new SampleStringParser(APRS);
String Tokens = ssp.parse(">") + "\n" +
ssp.parse(",") + "\n" +
ssp.parse(",") + "\n" +
ssp.parse(",") + "\n" +
ssp.parse("@") + "\n" +
ssp.parse("z") + "\n" +
ssp.parse("/") + "\n" +
ssp.parse("W") + "\n" +
ssp.parse("/") + "\n" +
ssp.parse("g") + "\n" +
ssp.parse("t") + "\n" +
ssp.parse("r") + "\n" +
ssp.parse("P") + "\n" +
ssp.parse("p") + "\n" +
ssp.parse("h") + "\n" +
ssp.parse("b") + "\n" +
ssp.parse("v");
System.out.println("");
StringTokenizer token = new StringTokenizer(Tokens, "\n", false);
String[] stringAry = new String[token.countTokens()];
for(int i = 0;token.hasMoreTokens(); i++)
{
stringAry<i> = token.nextToken();
System.out.println(stringAry<i>);
}
String[] temp = stringAry;
stringAry = new String[temp.length-3];
System.out.println("");
stringAry[0] = temp[0];
System.out.println(stringAry[0]);
for(int i = 5, b =1; i < temp.length; i++, b++)
{
stringAry<b> = temp<i>;
System.out.println(stringAry<b>);
}
ArrayList<String> aryList = new ArrayList<String>();
for(int i = 0; i < stringAry.length; i++)
{
aryList.add(stringAry<i>);
}
stringAry = aryList.toArray(new String[0]);
return stringAry;
}
}
biojaea at 2007-7-10 14:18:32 >
