intefer is an integer.
array is a predefined array of intefegers.,
Now, please tell me if this is ok:
array[0] = intefer;
will the first number in array now become intefer ?
I've got this massive error and I can鑤 figure out what's the case...I hope this will solve my problems...
> intefer is an integer.
>
> array is a predefined array of intefegers.,
What is a "predefined array"?
> Now, please tell me if this is ok:
>
> array[0] = intefer;
It depends on what came before that to define and initialize array.
> will the first number in array now become intefer ?
If you did everything right before that, yes.
> I've got this massive error and I can鑤 figure out
> what's the case...I hope this will solve my
> problems...
It would help if you'd post the actual errors, and more of your code.
When you post code, please use[code] and [/code] tags as described in [url=http://forum.java.sun.com/help.jspa?sec=formatting]Formatting tips[/url] on the message entry page. It makes it much easier to read.
I'm not allowed to post my code :( at least not everything
I guess I did everything right...............
This is what I want to do....I want the program to read three variables from three different files....And I did that, for sure, tested it, it's ok.
Now, I want the computer to bubble sort the files that it has already read from the files and print them to the user from the highest value to the lowest....What I did now is I assigned every entered value in one array (first values entered is array[0],, second array[1], etc)
now this is how I figured I'd bubble sort>
[quote]for (int v=0;x<3;x++){
for (int y=0;y<3;y++){
if (array[y] > array[y+1]){
temp = array[y+1];
arrayf[y+1] = array[y];
array[y]]= temp;}}}
[/quote]
but for some odd reason it does not work. I get this error>
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 5
how on earth? I-be been struggling with this problem for a souple of hours now, and I need to solve this, because if I do, I've finished my program !
btw about the exception....
catch(IOException io){
System.out.println("Error")
}
Message was edited by:
me
its hard to preditct without seeing your whole code. anyway try this. make some changes in your second for loop statement.
for (int y=0;y<3-1-i;y++){
Message was edited by:
fastmike
> its hard to preditct without seeing your whole code.
> anyway try this. make some changes in your second for
> loop statement.
> > for (int y=0;y<3-1-i;y++){
>
>
> Message was edited by:
> fastmike
but I have that, don't I ?
I can-t post my code :(
Don't ask, rules are rules
anyway, the rest of the code is no problem....I had the program working, but then I figure I need to bubble sort the information read from the files...and then I added arrays and the code above and hell started...
HALP !
(I know I misspelled help)
> > I guess I did everything right...............
>
> Obivously not. But if you won't tell us exactly what
> you did (that is, by posting your exact code and
> error message) then it's impossible to give you any
> help other than general pointers.
I have posted every thing needed. Even the error message it get! Note that I get that message when running the program, not when compiling
> I have posted every thing needed.
Okay. There's nothing in the code you posted that will attempt to access array[5]. And it won't even attempt to access arrayf[5] either -- I don't think you should be working with the two different arrays in your swapping code, but that wouldn't cause the exception you posted.
> > > I guess I did everything right...............
> >
> > Obivously not. But if you won't tell us exactly
> what
> > you did (that is, by posting your exact code and
> > error message) then it's impossible to give you
> any
> > help other than general pointers.
>
> I have posted every thing needed.
No, you haven't.
> its hard to preditct without seeing your whole code.
> anyway try this. make some changes in your second for
> loop statement.
> > for (int y=0;y<3-1-i;y++){
>
>
> Message was edited by:
> fastmike
OPen your eyes soldier !
> > its hard to preditct without seeing your whole
> code.
> > anyway try this. make some changes in your second
> for
> > loop statement.
> > > > for (int y=0;y<3-1-i;y++){
> >
> >
> > Message was edited by:
> > fastmike
>
> but I have that, don't I ?
>
> I can-t post my code :(
>
> Don't ask, rules are rules
>
> anyway, the rest of the code is no problem....I had
> the program working, but then I figure I need to
> bubble sort the information read from the files...and
> then I added arrays and the code above and hell
> started...
>
> HALP !
>
> (I know I misspelled help)
Open your eyes soldier !
This is what I want to do....I want the program to read three variables from three different files....And I did that, for sure, tested it, it's ok.
Now, I want the computer to bubble sort the files that it has already read from the files and print them to the user from the highest value to the lowest....What I did now is I assigned every entered value in one array (first values entered is array[0],, second array[1], etc)
for (int x=0;x<3;x++){
for (int y=0;y<3;y++){
if (array[y] > array[y+1]){
temp = array[y+1];
arrayf[y+1] = array[y];
array[y]]= temp;} } }
I'm certain that the previous code is ok, since it worked fine before I wanted to sort. I'm having problems sorting the information. Is everything ok with the information I have posted so far?
I'm not trolling! I just cannot post my code... :*(
--
I-ve just read the post....than you for your help, but I still have problems :(
I don-t have anything else that deals with the arrays...ah, thansk anyway
Message was edited by:
Emir
Message was edited by:
Emir
> for (int x=0;x<3;x++){
> for (int y=0;y<3;y++){
> if (array[y] > array[y+1]){
> temp = array[y+1];
> arrayf[y+1] = array[y];
> array[y]]= temp;} } }
>
>
What does the for loop with x do ? I don't see the x variable referenced ever.
> > for (int x=0;x<3;x++){
> > for (int y=0;y<3;y++){
> > if (array[y] > array[y+1]){
> > temp = array[y+1];
> > arrayf[y+1] = array[y];
> > array[y]]= temp;} } }
> >
> >
> What does the for loop with x do ? I don't see the x
> variable referenced ever.
I ensured that the loop with the variable y will get executed a couple of time, in order for it to be sure that the data is sorted.
