regex

String s1 = "abcfromCharCodedef";

String s2 = "abcString.fromCharCodedef";

String regex = ".*[^String\\.]fromCharCode.*";

System.out.println(s1.matches(regex));

System.out.println(s2.matches(regex));

prometheuzza at 2007-7-10 2:55:55 >

You need to say how you are going to use this regex because this meets your specification but I don't think it is what you want.String regex = "(?!String\\.)fromCharCode";

System.out.println("String.fromCharCode".matches(regex));

System.out.println("fromCharCode".matches(regex));

sabre150a at 2007-7-10 2:55:56 >

> You need to say how you are going to use this regex

> because this meets your specification but I don't

> think it is what you want.> String regex = "(?!String\\.)fromCharCode";

> System.out.println("String.fromCharCode".matches(regex

> ));

>

> ystem.out.println("fromCharCode".matches(regex));

>

:-( Ignore this! It is rubbish!

sabre150a at 2007-7-10 2:55:56 >

> > > String regex = ".*[^String\\.]fromCharCode.*";

> >

> > Is that expression really correct? I would use

> > negative look behind.

> >

> > Kaj

>

> I quickly tried my solution (once) and it worked.

> However, my knowledge of the dark regex-force is very

> limited*, so you are probably right.

I don't know much either about regexp, but I'm learning :)

One of the problems of your regexp is [^String\\.] that doesn't do what you think it does (if I'm correct). It creates a character class which will match any character except for S t r i n g \ and .

(And it will not care about the order of the characters)

Kaj

kajbja at 2007-7-10 2:55:56 >

> I don't know much either about regexp, but I'm

> learning :)

Me too. I really have to read a decent regex book soon!

> One of the problems of your regexp is [^String\\.]

> that doesn't do what you think it does (if I'm

> correct). It creates a character class which will

> match any character except for S t r i n g \ and .

> (And it will not care about the order of the

> characters)

>

> Kaj

Ah, I understand. Thanks Kaj.

prometheuzza at 2007-7-10 2:55:56 >

I plan to continue my regex studies after I'm dead, eventually to achieve ultimate, blissful mastery. But don't let that discourage you; rather, my hope is to inspire others to strive for excellence, for my name is really Jonathan Livingston Hacker.

BTW, the backslashes in "[^String\\.]" won't match a literal backslash. They just escape the dot, which doesn't need to be escaped when it appears in a character class. Inside a character class or out, you have to use four backslashes to match one (when you're writing the regex in the form of a String literal, that is).

uncle_alicea at 2007-7-21 18:15:16 >

> I plan to continue my regex studies after I'm dead,

> eventually to achieve ultimate, blissful mastery.

> But don't let that discourage you; rather, my hope

> is to inspire others to strive for excellence, for

> my name is really Jonathan Livingston Hacker.

Uncle_alice will live on as a self-aware, self-documenting, artificially intelligent Perl script with aspirations of world domination. He will rewrite and recompile himself to native code on demand.

kevjavaa at 2007-7-21 18:15:16 >