Hi
I stored a float into a ByteBuffer and I would like to read the Bytes (not float value) from the ByteBuffer.
I tried to do this
float Numb = 20;
buffer.putFloat(Numb);
byte a[] = new byte[4];
buffer.get(a, 0, a.length);
System.out.println(a.toString());
But I get in the console : [B@3e25a5
Thanks
Stan
for(int i = 0; i < a.length; i++)
{
System.out.print(a[i]);
}
System.out.println();
or
for(byte b : a)
{
System.out.print(b);
}
System.out.println();
you are calling toString on an object (an array of type byte), thus getting the string representation of the array object itself, instead of the values of the elements of the array.
~Tim
> Hi Tim !
>
> thx for your answer. It seems to work but I get now
> in the console this: 65-9600
>
> Is it a format problem ?
>
> regards
>
> Stan
Sort of. The values are 65,-96,0,0 and when you print them out, they are all squished together, since the print doesn't contain any formatting.
~Tim
Hi,
you are right, the numbers are all squished.
But they aren't the expected numbers... I expect to print the binary representation from my Bytebuffer.
I stored a float into a ByteBuffer, so that the float would be convert in Byte. And I try to show the Bytes which are into the ByteBuffer.
Thx
Stan
Then most likely your expectation is wrong. This could be because you didn't realize that bytes are signed in Java, or because you got your endian-ness wrong, or because you don't understand what the bytes are in a float, or for some other reason. But it's impossible to tell without knowing what you did, what you expected to see, and what you actually saw.
> It seems to be curious, but the numbers that I
> expected were more a binary sequence....
I have asked you twice what you expect. So that answer tells me that you haven't a clue what to expect. Am I right? Or does that "binary sequence" business mean that you just want the bytes represented in hexadecimal or binary or something?
