Classic Network-related computing problem

Here is a challenge that rewards the best answer with $10,000 and their code in Borland's developer magazine each year. It's not easy!

Networks are complex. Transporting data from point A to point B in the shortest time and traveling the smallest distance.

Here, we have two variables - Speed (S) and Distance (D). Now, the general rule one might think is that as D increases S decreases. That is incorrect, an so is the inverse.

A Link (L) can have a different D and S then another L connected to it, and there may be many L connected to each other.

A Route (R) is any path between point A and point B. It can have 1 or more L.

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Best Route (B) = (first D+S)+(last D+S)^(Avg. D + Avg. S)/(Number of Links Traveled)

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Therefore, the Best Route has the lowest number of links and the highest average speed.

Good luck, and may the network be with you.

[1050 byte] By [watertownjordana] at [2007-9-28 11:26:31]
# 1

> Here is a challenge that rewards the best answer with

> $10,000 and their code in Borland's developer magazine

> each year. It's not easy!

I think the best answer will be rewarded by achieving the honor of being the outcome of your homework... you don't expect us to do your homework, do you?!

if this isn't a fake, point us to the official site of this challenge, maybe we might help you then... maybe...

greetings, sebastian

SebastianMa at 2007-7-12 2:01:05 > top of Java-index,Other Topics,Algorithms...