Regarding System Proces
I am working on a java based project. I have one problem, My application is based on OSGI frame work.
So when user start the application i have to do the following....
Look for port 80 if any server/services is there i have to kill that service. And Start my small http server on it.
So i am not able to get the handle for the process in java to kill the service through my application. I have to make this work on windows and linux.
Can any one tell me how to start with this.
thanks
[521 byte] By [
javajain] at [2007-9-27 19:16:35]
The crucial point is how to know which process listens on a given port. If you know that (and have the appropriate privileges) you can "kill" the process in the appropriate platform-specific way.
On Unix/Linux you know what ports are listened on:
$ netstat -na|grep -i listen|grep tcp
tcp00 0.0.0.0:513 0.0.0.0:*LISTEN
tcp00 0.0.0.0:37 0.0.0.0:*LISTEN
tcp00 0.0.0.0:79 0.0.0.0:*LISTEN
tcp00 0.0.0.0:60000.0.0.0:*LISTEN
tcp00 0.0.0.0:12340.0.0.0:*LISTEN
tcp00 0.0.0.0:21 0.0.0.0:*LISTEN
tcp00 0.0.0.0:23 0.0.0.0:*LISTEN
tcp00 :::22:::*LISTEN
Wow! 1234 looks cool! Who is there?
$ fuser -n tcp 1234
1234/tcp: 3088
And what is porcess 3088?
$ ps -p 3088 -f
UIDPID PPID C STIME TTY TIME CMD
ijbalazs 30881 0 Sep16 pts/200:00:05 /usr/lib/jdk1.2.2/bin/i386/green_threads/java -classpath /home/ijbalazs/source/java/ZipServer ZipServer 1234
Okay, now I remember: it is a java program, a "ZipServer": a little web server (written in Java) which serves requests from zip-archives. Thus I (and potentially others on this side on the firewall) can browse for example the various java documentations without having to unzip them.
BIJ at 2007-7-6 21:50:17 >
