How to explain this?

My bfin.read() reads bytes much less than assigned 4096?

FileInputStream fis = new FileInputStream(fileFrom);

bfin = new BufferedInputStream(fis,4096);

while (true) {

if ( (nbytes = bfin.read()) == -1) break;

System.out.println("nbytes: " + nbytes );

}

Here is the output:

...

nbytes: 117

nbytes: 56

nbytes: 15

nbytes: 134

nbytes: 41

nbytes: 69

nbytes: 176

nbytes: 60

nbytes: 21

nbytes: 9

nbytes: 198

nbytes: 242

nbytes: 166

nbytes: 56

nbytes: 119

nbytes: 52

nbytes: 101

nbytes: 38

nbytes: 203

...

Thanks

[694 byte] By [learnj1] at [2007-9-26 3:25:22]

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# 1

read() reads one byte and returns it. It does not return the number of bytes read.

schapel at 2007-6-29 11:46:07 >

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# 2

The BufferedInputStream.read() method you're using reads the next single byte from the stream and returns it as the function value. Try this instead: FileInputStream fis = new FileInputStream(fileFrom);

bfin = new BufferedInputStream(fis,4096);

byte[] buf = new byte[4096] ;

int nbytes ;

while (true) {

if ( (nbytes = bfin.read(buf)) < 0) break ;

System.out.println("nbytes: " + nbytes );

}

DragonMan at 2007-6-29 11:46:07 >

# 3

Hi, DragonMan if we add byte[] buf = new byte[4096], what is it (the other 4096) for inside bfin = new BufferedInputStream(fis,4096) ?Thnx

learnj1 at 2007-6-29 11:46:08 >

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